How do you factor #9b^2-36#?

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Answer 1 · 2015-05-04T07:16:07

#9b^2 - 36# can be written as #(3b)^2 - (6)^2#

this is of the form:

#a^2 - b^2 = ( a + b) (a -b ) #

here: #a = 3b# and # b = 6#

so ,

# (3b)^2 - (6)^2= (3b +6) (3b - 6) #

the factorized form of #9b^2 - 36# is:

#(3b +6) (3b - 6) #