How do you factor $8 z^{2} + 16 z - a z - 2 a$ $8z^2 + 16z - az - 2a$ ?

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How do you factor $8 z^{2} + 16 z - a z - 2 a$ $8z^2 + 16z - az - 2a$ ?

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Answer 1 · 2018-05-02T19:31:51

$(z + 2) (8 z - a)$ $(z+2)(8z-a)$

Explanation:

$factor by grouping$ $color(blue)"factor by grouping"$

$\Rightarrow 8 z (z + 2) - a (z + 2)$ $rArrcolor(red)(8z)(z+2)color(red)(-a)(z+2)$

$take out the common factor (z + 2)$ $"take out the "color(blue)"common factor "(z+2)$

$= (z + 2) (8 z - a)$ $=(z+2)(color(red)(8z-a))$

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How do you factor $8 z^{2} + 16 z - a z - 2 a$ $8z^2 + 16z - az - 2a$ ?

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How do you factor $8 z^{2} + 16 z - a z - 2 a$ $8z^2 + 16z - az - 2a$ ?