How do you factor #8y^3+ 1#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Nityananda Mar 9, 2018 #(2y+1)(4y^2-2y+1)# Explanation: Given, #8y^3+1# #rArr (2y)^3+(1)^3# #rArr (2y+1)^3-3.2y.1(2y+1)# #rArr (2y+1)[(2y+1)^2-6y]# #rArr (2y+1)[4y^2+4y+1-6y]# #rArr (2y+1)(4y^2-2y+1)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 5090 views around the world You can reuse this answer Creative Commons License