How do you factor #8x^6-32x^5+4x^4#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Nghi N. May 13, 2015 #y = 4x^4.(2x^2 - 8x + 1)# The trinomial in parentheses can't be factored because #D = b^2 - 4ac = 64 - 8 = 56# is not a perfect square. Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1443 views around the world You can reuse this answer Creative Commons License