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How do you factor #8x^3*y^6 + 27#?

1 Answer

Dec 13, 2015

#(2xy^2+3)(4x^2y^4-6xy^2+9)#

Explanation:

Sum of cubes: #(a^3+b^3)=(a+b)(a^2-ab+b^2)#

Since #8x^3y^6+27=(2xy^2)^3+(3)^3#,

#a=2xy^2#
#b=3#

#8x^3y^6+27=(2xy^2+3)(4x^2y^4-6xy^2+9)#

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