How do you factor #8x^3 - 27y^3#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Nghi N. · Meave60 Jun 10, 2015 #8x^3 - 27y^3=(2x-3y)(4x^2+6xy+9y^2)# Explanation: Use the identity #a^3 - b^3 = (a - b)(a^2 + ab + b^2)# #a=2x# #b=3y# #8x^3 - 27y^3 = (2x - 3y)(4x^2 + 6xy + 9y^2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 31575 views around the world You can reuse this answer Creative Commons License