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How do you factor # 8x^2-18#?

1 Answer

Apr 4, 2018

#2(2x+3)(2x-3)#

Explanation:

First, factor out the GCF (2)

#2(4x^2-9) rarr 4x^2-9# can be factored out using difference of squares:

#a^2-b^2=(a-b)(a+b)#

#a# in this case is #2x#, #b# is #3#

#(2x-3)(2x+3)#

#2(2x-3)(2x+3)#

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