How do you factor $8m^3-p^3$ ?

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Answer 1 · 2018-03-03T07:08:12

$(2m - p)(4m^2+2mp+p^2)$

$a^3 - b^3 = (a-b)(a^2+ab+b^2)$
$"So here we have"$
$a = 2 m$
$b = p$
$"So we get"$
$(2m - p)(4m^2+2mp+p^2)$

How do you factor 8m^3-p^38m^3-p^3?