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How do you factor #7x^2-847#?

1 Answer

Feb 17, 2017

You first try to divide #847div7=121#

Explanation:

So we now have
#=7*(x^2-121)#

Notice that #121=11^2# and you get the special product for the difference of two squares: #a^2-b^2=(a+b)(a-b)#:

#=7(x+11)(x-11)#

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