How do you factor #6xr+2xs+3yr+ys#?
1 Answer
Apr 28, 2017
Explanation:
#"factorise by 'grouping' "#
#color(red)(6xr+2xs)color(magenta)(+3yr+ys)#
#=color(red)(2x)(3r+s)+color(magenta)(y)(3r+s)#
#(3r+s)" is a common factor to both groups"#
#=(3r+s)(color(red)(2x)+color(magenta)(y))#
#rArr6xr+2xs+3yr+ys=(3r+s)(2x+y)#
