How do you factor #6x^3 - 36x^2 - 162x#?

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How do you factor #6x^3 - 36x^2 - 162x#?

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Answer 1 · 2015-06-04T20:58:14

#6x^3-36x^2-162x = 6x(x^2-6x-27)#

#= 6x(x^2-(9-3)x-(9xx3)) = 6x(x-9)(x+3)#

Having separated the common #6x# factor out, it remained to try to find a factorization of #27# into two factors whose difference was #6#. There are not many choices to try and the pair #9, 6# works.

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How do you factor #6x^3 - 36x^2 - 162x#?

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