How do you factor $6x^2 - 11x + 2 = 0$ ?

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Answer 1 · 2017-07-18T15:06:06

$y = 6x^2 - 11x + 2 = 0$
$D = b^2 - 4ac = 121 - 48 = 73$
Since D isn't a perfect square, this trinomial can't be factored.

How do you factor 6x^2 - 11x + 2 = 0 6x^2 - 11x + 2 = 0?