How do you factor #6x^2-10x+24#?

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How do you factor #6x^2-10x+24#?

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Answer 1 · 2016-05-16T00:42:11

#2(3x^2 - 5x + 12)#

Explanation:

#f(x) = 2y = 2(3x^2 - 5x + 12)#
Factor y, the trinomial in parentheses, by the new AC Method (Socratic Search)
#y = 3x^2 - 5x + 12#
#D = b^2 - 4ac = 25 - 144 = -119.#
Since D < 0, this trinomial y can't be factored.
#f(x) = 2y = 2(3x^2 - 5x + 12)#

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How do you factor #6x^2-10x+24#?

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