How do you factor #64x² - 81y²#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Gió May 28, 2015 You can use the notable: #a^2-b^2=(a-b)(a+b)# in your case: #64x^2-81y^2=(8x-9y)(8x+9y)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 3010 views around the world You can reuse this answer Creative Commons License