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How do you factor #64-t^3#?

1 Answer

Apr 30, 2016

#=(4-t)(16+4t+t^2)#

Explanation:

#64-t^3#
#=4^3-t^3#
#=(4-t)(4^2+4t+t^2)#
#=(4-t)(16+4t+t^2)#

(using formula #a^3-b^3=(a-b)(a^2+ab+b^2)#

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