How do you factor 64+27t^3?

1 Answer
Jim G.
Apr 9, 2016

(4 + 3t)(16 - 12t + 9t^2 )

Explanation:

This is a color(blue)" sum of 2 cubes " " and factors as follows "

a^3 + b^3 = color(red)(|bar(ul(color(white)(a/a)color(black)((a+b)(a^2-ab+b^2)color(white)(a/a)|)))

For 64 + 27t^3 , " a = 4" and b = 3t "

substituting these values into the factored form.

rArr 64 + 27t^3 = (4 + 3t)(16 - 12t + 9t^2)

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