How do you factor #5x^2 + 13x - 6#?

1 Answer
SCooke
May 4, 2018

#(5x - 2)(x + 3)#

Explanation:

If it is factorable, separate the terms into the form of:
#(ax + b)(cx + d)#e
Where #axxc=# the coefficient on #x^2#;
#bxxd =#the constant term;
and #(axxc)+(bxxd)=#the coefficient on the #x# term.

In this case, we have:
#(5x - 2)(x + 3)#

From there we can also find the solution, or "roots" to the equation by setting each factor equal to zero.
#5x - 2 = 0# and
#x + 3 = 0#

Solution: #x = 2/5# and #x = -3#

Related questions
See all questions in Factorization of Quadratic Expressions
Impact of this question
11372 views around the world
You can reuse this answer
Creative Commons License