How do you factor #5n^2-22n+8#?
1 Answer
Jul 1, 2016
Explanation:
Use an AC method:
Find a pair of factors of
The pair
Use that pair to split the middle term and factor by grouping:
#5n^2-22n+8 = (5n^2-20n)-(2n-8)#
#=5n(n-4)-2(n-4)#
#=(5n-2)(n-4)#
