How do you factor $54 c^{3} d^{4} + 9 c^{4} d^{2}$ $54c^3d^4+9c^4d^2$ ?

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How do you factor $54 c^{3} d^{4} + 9 c^{4} d^{2}$ $54c^3d^4+9c^4d^2$ ?

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Answer 1 · 2018-06-16T18:17:06

$9 c^{3} d^{2} (6 d^{2} + c)$ $9c^3d^2(6d^2+c)$

Explanation:

We check it by expanding:
$9 c^{3} d^{2} (6 d^{2} + c) = 54 c^{3} d^{4} + 9 c^{4} d^{2}$ $9c^3d^2(6d^2+c)=54c^3d^4+9c^4d^2$

Answer 2 · 2018-08-09T23:12:11

$9 c^{3} d^{2} (6 d^{2} + c)$ $9c^3d^2(6d^2+c)$

Explanation:

Look at what power each $c$ $c$ and $d$ $d$ is raised to and take out the most that you can out of both of them:

there are at least three c's in both terms so you can pull out a $c^{3}$ $c^3$ and there are at least 2 d's in both terms so pull out $d^{2}$ $d^2$ . Finally there is a common factor 9 in both terms so we'll pull that out as well:

$9 c^{3} d^{2} (6 d^{2} + c)$ $9c^3d^2(6d^2+c)$

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How do you factor $54 c^{3} d^{4} + 9 c^{4} d^{2}$ $54c^3d^4+9c^4d^2$ ?

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Explanation:

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How do you factor $54 c^{3} d^{4} + 9 c^{4} d^{2}$ $54c^3d^4+9c^4d^2$ ?