How do you factor #54b^3+16#?
1 Answer
Aug 6, 2016
Explanation:
The sum of cubes identity can be written:
#x^3+y^3 = (x+y)(x^2-xy+y^2)#
Note that both
#54b^3+16#
#=2(27b^3+8)#
#=2((3b)^3+2^3)#
#=2(3b+2)((3b)^2-(3b)(2)+(2)^2)#
#=2(3b+2)(9b^2-6b+4)#
