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How do you factor #4x^2 -9#?

1 Answer

May 31, 2015

This is a difference of squares:

#4x^2-9 = (2x)^2 - 3^2#

So you can use the difference of squares identity

#a^2 - b^2 = (a-b)(a+b)#

to find...

#(2x)^2 - 3^2 = (2x-3)(2x+3)#

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