How do you factor #4x^2-16x+15#?

1 Answer
Shwetank Mauria
Jun 2, 2016

#4x^2-16x+15=(2x-3)(2x-5)#

Explanation:

To factorize #ax^2+bx+c#, one should split middle term in two parts, so that their product is #ac# and sum is #b#.

Hence in #4x^2-16x+15#, while the product should be #4xx15=60#, sum should be #-16#. It is apparent that these are #-6# and #-10#.

Hence #4x^2-16x+15#

= #4x^2-10x-6x+15#

= #2x(2x-5)-3(2x-5)#

= #(2x-3)(2x-5)#

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