How do you factor #-4x^2 +11x + 20#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Ratnaker Mehta Aug 28, 2016 #-(x-4)(4x+5)#. Explanation: Let #P(x)=-4x^2+11x+20#. We have, #4xx20=4xx4xx5=16xx5, & 16-5=11#. Therefore, #P(x)=ul(-4x^2+16x)-ul(5x+20)# #=-4x(x-4)-5(x-4)# #=(x-4)(-4x-5)# #=-(x-4)(4x+5)#. Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1826 views around the world You can reuse this answer Creative Commons License