How do you factor #4t^3-64t^2-128t#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Binayaka C. Aug 30, 2016 #4t(t-8+4sqrt6)(t-8-4sqrt6)# Explanation: #4t^3-64t^2-128t=4t(t^2-16t-32)=4t((t-8)^2-64-32)=4t((t-8)^2-96) =4t((t-8)^2-(4sqrt6)^2)=4t((t-8+4sqrt6)(t-8-4sqrt6))#[Ans] Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1091 views around the world You can reuse this answer Creative Commons License