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How do you factor #4m(4 - m) + 3n(4 - m)#?

1 Answer

Jun 2, 2018

#(4-m)(4m+3n) #

Explanation:

notice:

# 4mcolor(red)((4 - m )) + 3ncolor(red)(( 4 - m ) #

#color(red)( (4-m) ) # is common in each, this whole term can be factored out

#=> color(red)( (4-m) ) [ 4m + 3n ] #

#color(blue)( = ( 4-m )( 4m + 3n) #

This is the most simplified factorisation

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