How do you factor $4azc² - 8azc + 4az$ ?

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Answer 1 · 2016-06-06T05:59:15

$4az(c-1)(c-1)$

$4azc^2-8azc+4az$
$4az(c^2-2c+1)$
$4az(c^2-c-c+1)$
$4az(c(c-1)-1(c-1))$
$4az(c-1)(c-1)$

How do you factor 4azc² - 8azc + 4az4azc² - 8azc + 4az?