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How do you factor #4a^2-28a+48#?

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May 22, 2015

#4a^2-28a+48=4(a-3)(a-4)#

It's a quadratic so:

#Delta=(-28)^2-4*4*48=16#
#sqrt(Delta)=4#

#a_1=(-(-28)-4)/(2*4)=24/8=3#
#a_2=(-(-28)+4)/(2*4)=32/8=4#

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