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How do you factor $49 y^{4} - 64$ $49y^4 - 64$ ?

1 Answer

Konstantinos Michailidis

May 30, 2016

We have that

$49 y^{4} - 64 = {(7 y^{2})}^{2} - 8^{2} = (7 y^{2} - 8) (7 y^{2} + 8)$ $49y^4-64=(7y^2)^2-8^2=(7y^2-8)(7y^2+8)$

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