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How do you factor $49u^2 - (x-y) ^2$ ?

1 Answer

Konstantinos Michailidis

Apr 8, 2017

It is

$49u^2 - (x-y) ^2=(7u)^2-(x-y)^2=[7u+(x-y)]*[7*u-(x-y)]$

We make use of $a^2-b^2=(a+b)*(a-b)$

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