How do you factor #49u^2 - (x-y) ^2#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Konstantinos Michailidis Apr 8, 2017 It is #49u^2 - (x-y) ^2=(7u)^2-(x-y)^2=[7u+(x-y)]*[7*u-(x-y)]# We make use of #a^2-b^2=(a+b)*(a-b)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1429 views around the world You can reuse this answer Creative Commons License