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How do you factor #49a^2 - 81b^2#?

1 Answer

Jul 9, 2015

You may notice that #49=7^2and81=9^2# are both squares.

Explanation:

So #49a^2=(7a)^2and81b^2=(9b)^2# are also squares, and then we can use the special product of the form: #x^2-y^2=(x+y)(x-y)#

#=(7a+9b)(7a-9b)#

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