How do you factor: #3y - 6x + 4xy - 2y^2#?

1 Answer
Jim G.
Aug 29, 2016

#(y-2x)(3-2y)#

Explanation:

Group the terms in 'pairs'

That is #[3y-6x]+[4xy-2y^2]#

now factorise each 'pair' by taking out a #color(blue)"common factor"#

#rArrcolor(red)(3)(y-2x)color(red)(-2y)(y-2x)#

We now have a #color(blue)"common factor"# of (y - 2x)

#rArr(y-2x)(color(red)(3-2y))#

#rArr3y-6x+4xy-2y^2=(y-2x)(3-2y)#

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