How do you factor #3y^4-2y^2-5# completely? Algebra Polynomials and Factoring Factoring Completely 1 Answer Binayaka C. Jun 13, 2018 # 3 y^4 - 2 y^2 -5 = (y^2+1)(3 y^2 - 5)# Explanation: # 3 y^4 - 2 y^2 -5 # #= 3 y^4 + 3 y^2 - 5 y^2-5# #= 3 y^2(y^2+1) - 5( y^2+1)# #= (y^2+1)(3 y^2 - 5)# [Ans] Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 2297 views around the world You can reuse this answer Creative Commons License