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How do you factor #-3xy^6 + 3xy^2#?

1 Answer

Konstantinos Michailidis

Sep 11, 2015

It is #3xy^2(1-y)(1+y)(1+y^2)#

Explanation:

We have that

#-3xy^6+3xy^2=>3xy^2(-y^4+1)=>3xy^2(1-y^2)(1+y^2)=>3xy^2(1-y)(1+y)(1+y^2)#

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