How do you factor #-3x(x-2)+4x(x+1)+9#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Tony B Jun 24, 2016 #(x+1)(x+9)# Explanation: Multiply out the brackets #-3x^2+6x" "+4x^2+4x" "+9# #4x^4-3x^2+6x+4x+9# #x^2+10x+9# Notice that #1xx9=9" and that "1+9=10# #(x+1)(x+9)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 954 views around the world You can reuse this answer Creative Commons License