How do you factor $3 x^{3} y^{2} - 2 x^{2} y + 5 x y$ $3x^3y^2 - 2x^2y + 5xy$ ?

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Answer 1 · 2016-08-28T20:29:17

$3 x^{3} y^{2} - 2 x^{2} y + 5 x y = x y (3 x^{2} y - 2 x + 5)$ $3x^3y^2-2x^2y+5xy=xy(3x^2y-2x+5)$

Note that all of the terms are divisible by $x y$ $xy$ , so:

$3 x^{3} y^{2} - 2 x^{2} y + 5 x y = x y (3 x^{2} y - 2 x + 5)$ $3x^3y^2-2x^2y+5xy=xy(3x^2y-2x+5)$

There are no simpler factors.

How do you factor 3x^3y^2 - 2x^2y + 5xy3x3y2−2x2y+5xy3x^3y^2 - 2x^2y + 5xy?