How do you factor #3x^3 + 2x^2 - 27x - 18#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Shwetank Mauria Jul 2, 2016 #3x^3+2x^2-27x-18=(x+3)(x-3)(3x+2)# Explanation: #3x^3+2x^2-27x-18# = #x^2(3x+2)-9(3x+2)# = #(x^2-9)(3x+2)# = #(x^2-3x+3x-9)(3x+2)# = #(x(x-3)+3(x-3))(3x+2)# = #(x+3)(x-3)(3x+2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 3786 views around the world You can reuse this answer Creative Commons License