How do you factor $3x^2 z – 3zx – 18z$ ?

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Answer 1 · 2018-04-25T18:40:44

$3z(x + 1)(x - 3)$

first, we can see that $3z$ is a common factor in all three terms. isolate that out and factor the rest.

$3x^2z - 3zx - 18z$

$3z(x^2 - x - 6)$

$3z(x + 1)(x - 3)$

Answer 2 · 2018-04-25T18:50:47

$3z(x-3)(x+2)$

$"take out the "color(blue)"common factor "3z$

$=3z(x^2-x-6)$

$"the factors of - 6 which sum to - 1 are - 3 and + 2"$

$=3z(x-3)(x+2)$

How do you factor 3x^2 z – 3zx – 18z 3x^2 z – 3zx – 18z?