How do you factor #3x^2+4x+1#??

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Answer 1 · 2015-12-09T01:19:19

#3x^2+4x+1=(3x+1)(x+1)#

#3x^2+4x+1# is a quadratic equation in the form #ax^2+bx+c#, where #a=3, b=4, and c=1#.

Use the AC method to factor the equation.

Multiply #a# times #c#.

#3xx1=3#

Find two numbers that when added equal #4# and when multiplied equal #3#. The numbers are #3# and #1#.

Rewrite the equation, substituting the middle term (b) with #3x# and #x#.

#3x^2+3x+x+1#

Group the terms into two groups.

#(3x^x+3x)+(x+1)#

Factor #3x# out of the first group.

#3x(x+1)+(x+1)#

Factor out #(x+1)#

#(3x+1)(x+1)#