How do you factor #3x^2 - 27(2-x)^2#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Deepak G. Aug 7, 2016 #=-12(x-3)(2x-3)# Explanation: #3x^2-27(2-x)^2# #=3x^2-27(4+x^2-4x)# #=3x^2-27(4)-27x^2+27(4x)# #=3x^2-108-27x^2+108x# #=-24x^2+108x-108# #=-12(2x^2-9x+9)# #=-12(2x^2-6x-3x+9)# #=-12(2x(x-3)-3(x-3))# #=-12(x-3)(2x-3)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 5478 views around the world You can reuse this answer Creative Commons License