How do you factor 3x2+10xy−25y2? Algebra Polynomials and Factoring Factoring Completely 1 Answer George C. Jul 6, 2015 3x2+10xy−25y2=(3x−5y)(x+5y) Explanation: If 3x2+10xy−25y2 has factors with integer coefficients, then they will take the form: 3x2+10xy−25y2=(3x+ay)(x+by) =3x2+(3b+a)xy+aby2 Since ab=−25, the possible (a,b) values are: (−25,1), (−5,5), (−1,25), (1,−25), (5,−5), (25,−1) These give values for 3b+a of: −22, 10, 74, −74, −10, 22 So choose a=−5 and b=5 to get the correct coefficient of xy Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x2−8? Which method do you use to factor 3x(x−1)+4(x−1)? What are the factors of 12x3+12x2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c2−75 completely? How do you factor x6−26x3−27? How do you factor 100x2+180x+81? See all questions in Factoring Completely Impact of this question 1748 views around the world You can reuse this answer Creative Commons License