How do you factor 3v^2+14v+8 ?

1 Answer
Nghi N.
May 16, 2015

y = 3v^2 + 14v + 8.= (x - p)(x - q)
I use the new AC Method to factor trinomials (Google, Yahoo Search)

Converted trinomial: y' = v^2 + 14v + 24 = (x -p')(x - q') (a,c = 24)
Compose factor pairs of 24: (1, 24)(2, 12). This sum is 14 = b. Then
p' = 2 and q' = 12. Back to original trinomial: p = (p')/a = 2/3, and q = (q')/a = 12/3 = 4.

Factored form: y = (x + 2/3)(x + 4) = (3x + 2)(x + 4)

Check by developing
y = 3x^2 + 12x + 2x + 8) = 3x^2 + 14x + 8 . OK

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