How do you factor #3cd – 6cy + 2xd – 4xy#?

1 Answer
Tony B
Mar 23, 2016

#(d-2y)(3c+2x)#

Explanation:

It is a matter of spotting the grouping and perhaps a bit of experimenting

#3c(d-2y)+2x(d-2y)" "# I struck lucky first time

The common factor is #(d-2y)# so we have

#(d-2y)(3c+2x)#

'~~~~~~~~~~~~~~~~~~~~~~~
Check:#" "(d-2y)(3c+2x) =3dc+2xd-6yc-4yx" " # It matches so ok!

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