How do you factor #36x^3-9x#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Tony B May 20, 2016 #9x(2x-1)(2x+1)# Explanation: Note that #4xx9=36# #=>9x(4x^2-1)# Consider the standard form of #" "a^2-b^2=(a-b)(a+b)# Note that #4x^2 -> (2x)^2" and " 1=1^2# #9x[ (2x)^2-1^2]# #9x(2x-1)(2x+1)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1973 views around the world You can reuse this answer Creative Commons License