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How do you factor #32x^2 – 8#?

1 Answer

May 13, 2015

#8# is a common factor to both the terms in the expression:

#32x^2 - 8 = 8(4x^2 - 1)#

# = 8((2x)^2 - 1^2)#

We know that #color(blue)(a^2 - b^2 = (a+b)(a-b)#

Hence the above expression can be written as :

# = color(green)(8(2x+1)(2x-1)#

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