How do you factor $3(2x-1)^2 (2) (x+3)^(1/2) + (2x-1)^3 (1/2) (x+3)^(-1/2)$ ?

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Answer 1 · 2015-10-09T04:56:16

$(7(2x-1)^2 (2x+5))/(2(x+3)^(1/2))$

Take out common factor $(2x-1)^2$ and simplify,

$(2x-1)^2 {6(x+3)^(1/2) + (2x-1)/(2(x+3)^(1/2)}}$

$(2x-1)^2{(12x+36 +2x-1)/(2(x+3)^(1/2)}}$

$((2x-1)^2 (14x+35))/(2(x+3)^(1/2))$

$(7(2x-1)^2 (2x+5))/(2(x+3)^(1/2))$

How do you factor 3(2x-1)^2 (2) (x+3)^(1/2) + (2x-1)^3 (1/2) (x+3)^(-1/2)3(2x-1)^2 (2) (x+3)^(1/2) + (2x-1)^3 (1/2) (x+3)^(-1/2)?