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How do you factor #2x^2 + x - 6#?

1 Answer

Jun 13, 2015

#2x^2+x-6 = (2x-3)(x+2)#

Explanation:

Let #f(x) = 2x^2+x-6#.

Notice that #f(-2) = 8-2-6 = 0#, so #(x+2)# is a factor.

The other factor must be #(2x-3)# to get the coefficient of #x^2# and the constant term when we multiply them...

#2x^2+x-6 = (2x-3)(x+2)#

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