How do you factor #2x^2 + x - 3 =0#?

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Answer 1 · 2017-02-07T21:34:09

#(x-1)(2x+3) = 0#

Given:

#2x^2+x-3 = 0#

Note that the sum of the coefficients is #0#. That is:

#2+1-3 = 0#

Hence #x=1# is a root and #(x-1)# a factor:

#0 = 2x^2+x-3 = (x-1)(2x+3)#