How do you factor #2x^2 -7x +3#?

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Answer 1 · 2015-11-08T18:51:57

#2x^2-7x+3=(2x-1)(x-3)#

#2x^2-7x+3# is a quadratic equation, #ax^2+bx+c#, where #a=2, b=-7, and c=3#.

Use the #a*c# method to factor this equation (also called splitting the middle).

Multiply #a# times #c#.

#2xx3=6#

Determine two numbers that when added equal #-7# and when multiplied equal #6#. The numbers #-x# and #-6# fit the criteria.

Rewrite the equation substituting #-x# and #-6x# for #-7x#.

#2x^2-x-6x+3=#

#x(2x-1)-3(2x-1)#

Factor out the common term #(2x-1)#

#(2x-1)(x-3)#