How do you factor #2x^2+3x+4#?

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How do you factor #2x^2+3x+4#?

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Answer 1 · 2015-10-28T05:28:41

This cannot be factored

Explanation:

There are no numbers which #4# and #2# can multiply together and add/subtract to #3#. However, it can be solved by using the quadratic formula #(-b+-sqrt(b^2-4(a)(c)))/(2(a))# where #a# is #2#, #b# is #3# and #c# is #4#

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How do you factor #2x^2+3x+4#?

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