How do you factor 2x^(2/3) - 5x^(1/3) - 3 = 0? Algebra Polynomials and Factoring Factoring Completely 1 Answer Konstantinos Michailidis Apr 15, 2016 Well notice that 3=5-2 hence 2x^(2/3) - 5x^(1/3) - 3 = 0=> 2x^(2/3)-5x^(1/3)-(5-2)=0=> 2*(x^(2/3)-1)-5(x^(1/3)-1)=0=> 2*(x^(1/3)+1)*(x^(1/3)-1)-5(x^(1/3)-1)=0=> (x^(1/3)-1)*[2(x^(1/3)+1)-5]=0 Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x^2-8? Which method do you use to factor 3x(x-1)+4(x-1) ? What are the factors of 12x^3+12x^2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c^2-75 completely? How do you factor x^6-26x^3-27? How do you factor 100x^2+180x+81? See all questions in Factoring Completely Impact of this question 1826 views around the world You can reuse this answer Creative Commons License