How do you factor #2x^(2/3) - 5x^(1/3) - 3 = 0#?

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How do you factor #2x^(2/3) - 5x^(1/3) - 3 = 0#?

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Answer 1 · 2016-04-15T00:45:01

Well notice that #3=5-2# hence

#2x^(2/3) - 5x^(1/3) - 3 = 0=> 2x^(2/3)-5x^(1/3)-(5-2)=0=> 2*(x^(2/3)-1)-5(x^(1/3)-1)=0=> 2*(x^(1/3)+1)*(x^(1/3)-1)-5(x^(1/3)-1)=0=> (x^(1/3)-1)*[2(x^(1/3)+1)-5]=0#

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How do you factor #2x^(2/3) - 5x^(1/3) - 3 = 0#?

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